(x+2)(2x+7)=2x^2+10x+2

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Solution for (x+2)(2x+7)=2x^2+10x+2 equation: 



(x+2)(2x+7)=2x^2+10x+2

We move all terms to the left:

(x+2)(2x+7)-(2x^2+10x+2)=0

We get rid of parentheses

-2x^2+(x+2)(2x+7)-10x-2=0

We multiply parentheses ..

-2x^2+(+2x^2+7x+4x+14)-10x-2=0

We get rid of parentheses

-2x^2+2x^2+7x+4x-10x+14-2=0

We add all the numbers together, and all the variables

x+12=0

We move all terms containing x to the left, all other terms to the right

x=-12

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